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Hoses are easier to allocate than pipes When there are no solid performance measurements at the start of a service, a safe approach is to look at the burst capability of all hosts at the site, limited by the capability of internal links and routers, and provision the hose to support that bandwidth This is their egress burst capability Continued performance monitoring can adjust the actual amount of bandwidth to be charged for, but you now have an adequate physical facility in place You will find that pipes and hoses are an excellent basic planning mechanism, but the proper, reliable distribution of traffic flows among pipes and hoses also requires network design using trunks Using trunks requires additional protocol mechanisms to supplement conventional routing

Reporting other expenses on the accrual basis Adding the net revenue or subtracting the expense of internal service funds

The type is a primitive data type The string argument is converted to a primitive value that corresponds to the WrapperType Otherwise a NumberFormatException is thrown if the string is not parsable

Boxing is a convenient way to wrap a primitive value in an object (see (1a) in Figure 102 and Section 51, p 162)

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If the amounts reported as net assets and changes in net assets in the proprietary fund nancial statements for total enterprise funds differ from the amounts of net assets and changes in net assets of business-type activities in the government-wide statement of activities, they should be explained on the face of the fund statement or in the notes (p) REPORTING GENERAL CAPITAL ASSETS General capital assets are capital assets of the government that are not speci cally related to activities reported in proprietary or duciary funds They are associated with and generally arise from governmental activities and usually result from expenditure of governmental fund nancial resources Nevertheless, they should not be reported as assets in governmental funds; instead, they should be reported in the governmental activities column in the government-wide statement of net assets

Let s walk through a very simplified pipe and hose provisioning exercise You are a small ISP with two POPs and one upstream (Figure 112) Your customers do have bandwidth guarantees to the upstream, which connects to you with a POS OC-192 (see Table 111) Physically, the OC-192 is provisioned for 8 Gbps of bandwidth and has an identical physical backup link

Character Boolean Integer Double charObj1 boolObj1 intObj1 doubleObj1 = = = = '\n'; true; 2008; 314;

Under GASB Statement No 34, a MD&A should be presented before the nancial statements are presented It should provide an objective and easily readable analysis of the government s nancial activities based on facts, decisions, or conditions of which management is aware as of the date of the auditor s report It should discuss the current-year results and compare them with the results of the prior year, including positive and negative aspects The use of charts, graphs, and tables is encouraged The MD&A should distinguish between information pertaining to the PG and that of its component units, focusing on the PG Whether to discuss matters related to a component unit should be based on its signi cance to the total of all discretely presented component units and to the PG MD&A requirements in GASB Statement No 34 are general to encourage effective reporting of only the most relevant information and to avoid boilerplate discussion The information presented should be con ned to the following eight items, including additional details pertaining to those

A constructor that takes a primitive value can be used to create wrapper objects (see (1b) in Figure 102)

Character Boolean Integer Double charObj1 boolObj1 intObj1 doubleObj1 = = = = new new new new Character('\n'); Boolean(true); Integer(2008); Double(314);

34 55

11

We can also use the valueOf() method that takes the primitive value to wrap as an argument (see (1c) in Figure 102)

.

Character Boolean Integer Double charObj1 boolObj1 intObj1 doubleObj1 = = = = CharactervalueOf('\n'); BooleanvalueOf(true); IntegervalueOf(2008); DoublevalueOf(314);

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